document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=803358>Question 803358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the function, f(x)=(x+2)^2, which is not one-to-one,<BR>\n" );
document.write( "a)  Restrict the function's domain so that the resulting function is one-one.\r<BR>\n" );
document.write( "\n" );
document.write( "b)Find the inverse of the function with the restricted domain.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484302 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Pick either the left side or the right side of the vertex.  This point is at (-2,0), so I will pick the left side of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%28x%29=%28x%2B2%29%5E2 ALIGN=MIDDLE  ALT=\"f%28x%29=%28x%2B2%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%3C=-2 ALIGN=MIDDLE  ALT=\"x%3C=-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  This will be one-to-one.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The cheap way to get its inverse is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%28y%2B2%29%5E2 ALIGN=MIDDLE  ALT=\"x=%28y%2B2%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%2B2=0%2B-+sqrt%28x%29%7D%7D%0D%0A%7B%7B%7By=-2%2B-+sqrt%28x%29 ALIGN=MIDDLE  ALT=\"y%2B2=0%2B-+sqrt%28x%29%7D%7D%0D%0A%7B%7B%7By=-2%2B-+sqrt%28x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, obtained from the  one-to-one function for x<=-2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "between <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-2-sqrt%28x%29 ALIGN=MIDDLE  ALT=\"y=-2-sqrt%28x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-2%2Bsqrt%28x%29 ALIGN=MIDDLE  ALT=\"y=-2%2Bsqrt%28x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, you want the one that is decreaing; looking at a graph would help...  It would be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y=-2-sqrt%28x%29%29 ALIGN=MIDDLE  ALT=\"highlight%28y=-2-sqrt%28x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28x%2B2%29%5E2%2C-2-sqrt%28x%29%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28x%2B2%29%5E2%2C-2-sqrt%28x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );