document.write( "Question 803333: a boat travels 1 km upstream and 1 km back. The time for the round trip is 5 hrs. the speed of the stream is 4 km/hr. what is the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #484293 by mananth(16946)\"\" \"About 
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boat speed x kph
\n" ); document.write( "current speed 4 kph
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\n" ); document.write( "against current x- 4 kph
\n" ); document.write( "with current x+ 4 kph
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\n" ); document.write( "Distance= 1 miles
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\n" ); document.write( "Time against + time with = 5 hours
\n" ); document.write( "t=d/r
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\n" ); document.write( "1 /( x + 4 ) + 1 /(x - 4 ) = 5
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\n" ); document.write( "LCD = (x - 4 ) ( x + 4 )
\n" ); document.write( "1 *( x - 4 ) + 1 (x + 4 ) = 5 (x^2 - 16 )
\n" ); document.write( "1 x - -4 + 1 x + 4 = 5 ( x ^2 - 16 )
\n" ); document.write( "2 x = 5 x ^2 -80
\n" ); document.write( "5 x ^2 - -2 x - 80
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\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 5 , b= -2 , c= -80
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\n" ); document.write( "b^2-4ac= 4 + 1600
\n" ); document.write( "b^2-4ac= 1604
\n" ); document.write( "\"%09sqrt%28%091604%09%29=%0940.05%09\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( 2 + 40.05 )/ 10
\n" ); document.write( "x1= 4.20
\n" ); document.write( "\"x2=%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x2=( 2 -40.05 ) / 10
\n" ); document.write( "x2= -3.80
\n" ); document.write( "Ignore negative value
\n" ); document.write( "boat speed 4.205 kph
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\n" ); document.write( "m.ananth@hotmail.ca
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