document.write( "Question 803333: a boat travels 1 km upstream and 1 km back. The time for the round trip is 5 hrs. the speed of the stream is 4 km/hr. what is the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #484293 by mananth(16946)![]() ![]() You can put this solution on YOUR website! boat speed x kph \n" ); document.write( "current speed 4 kph \n" ); document.write( " \n" ); document.write( "against current x- 4 kph \n" ); document.write( "with current x+ 4 kph \n" ); document.write( " \n" ); document.write( "Distance= 1 miles \n" ); document.write( " \n" ); document.write( "Time against + time with = 5 hours \n" ); document.write( "t=d/r \n" ); document.write( " \n" ); document.write( "1 /( x + 4 ) + 1 /(x - 4 ) = 5 \n" ); document.write( " \n" ); document.write( "LCD = (x - 4 ) ( x + 4 ) \n" ); document.write( "1 *( x - 4 ) + 1 (x + 4 ) = 5 (x^2 - 16 ) \n" ); document.write( "1 x - -4 + 1 x + 4 = 5 ( x ^2 - 16 ) \n" ); document.write( "2 x = 5 x ^2 -80 \n" ); document.write( "5 x ^2 - -2 x - 80 \n" ); document.write( " \n" ); document.write( "Find the roots of the equation by quadratic formula \n" ); document.write( " \n" ); document.write( "a= 5 , b= -2 , c= -80 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 4 + 1600 \n" ); document.write( "b^2-4ac= 1604 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( 2 + 40.05 )/ 10 \n" ); document.write( "x1= 4.20 \n" ); document.write( " \n" ); document.write( "x2=( 2 -40.05 ) / 10 \n" ); document.write( "x2= -3.80 \n" ); document.write( "Ignore negative value \n" ); document.write( "boat speed 4.205 kph \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |