document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68074>Question 68074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the area of a circle with a square (with side length of 2) inside of it? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48429 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you find the area of a circle with a square (with side length of 2) inside of it?<BR>\n" );
document.write( "Draw the picture and label the sides of the square.<BR>\n" );
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document.write( "Use Pythagoras: diagonal = sqrt(2^2+2^2)=sqrt8 = 2sqrt2<BR>\n" );
document.write( "So, the diagonal of the square is 2sqrt2.<BR>\n" );
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document.write( "That diagonal is the diameter of the circle.<BR>\n" );
document.write( "The area of the circle is pi* r^2.<BR>\n" );
document.write( "Area = pi* [(2sqrt2)/2]^2<BR>\n" );
document.write( "Area = pi*2<BR>\n" );
document.write( "Area of the circle is 2pi </SPAN>\n" );
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