document.write( "Question 802981: The volume of the smaller rectangular box is one-third the volume of the larger box. What is the value of X ?\r
\n" ); document.write( "\n" ); document.write( "The larger box has a volume of (x)*(x+2)*(x+1)
\n" ); document.write( "The smaller box is just shown in a figure with its length,width and height labeled as \"x\". \n" ); document.write( "
Algebra.Com's Answer #484269 by ankor@dixie-net.com(22740)\"\" \"About 
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The volume of the smaller rectangular box is one-third the volume of the larger box. What is the value of X ?\r
\n" ); document.write( "\n" ); document.write( "The larger box has a volume of (x)*(x+2)*(x+1)
\n" ); document.write( "The smaller box is just shown in a figure with its length,width and height = x
\n" ); document.write( "then
\n" ); document.write( "x^3 = vol of the small box
\n" ); document.write( ":
\n" ); document.write( "x^3 = \"1%2F3\"*x*(x+2)*(x+1)
\n" ); document.write( "get rid of the fraction multiply both sides by 3
\n" ); document.write( "3x^3 = x(x^2 + 3x + 2)
\n" ); document.write( "Divide both sides by x
\n" ); document.write( "3x^2 = x^2 + 3x + 2
\n" ); document.write( "Arrange as a quadratic equation on the left
\n" ); document.write( "3x^2 - x^2 - 3x - 2 = 0
\n" ); document.write( "2x^2 - 3x - 2 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(2x+1)(x-2) = 0
\n" ); document.write( "the positive solution is what we want here
\n" ); document.write( "x = 2
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if that works
\n" ); document.write( "2^3 = \"1%2F3\"*2*4*3
\n" ); document.write( "8 = \"1%2F3\"*24
\n" ); document.write( " \n" ); document.write( "
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