document.write( "Question 252016: Q.2:- Let ABC be a triangle in which AB=AC and let I be its in-centre. suppose BC=AB+AI.find the angle BAC? \n" ); document.write( "
Algebra.Com's Answer #484268 by plastery(3)![]() ![]() ![]() You can put this solution on YOUR website! The angle BAC that satisfies the relation BC=AB+AI is the right angle. \n" ); document.write( "To get to this solution with some trigonometry, let's call x the angle BAC and l the lenght of AB.. \n" ); document.write( "As the triangle ABC is isosceles and the sum of the internal angles of any triangle is 2 right angles, then the angle \n" ); document.write( "Let me remind that the Incenter of a triangle can be found as the intersection of any two internal angle bisectors. \n" ); document.write( "Let's call H the intersection of the bisector of BAC and BC. \n" ); document.write( "AH is also the altitude relative to the base BC. So ABH is a right triangle (right in H). \n" ); document.write( "For the definition of sine \n" ); document.write( "For the Pythagorean theorem \n" ); document.write( "The angle IBH is half of ABH that is \n" ); document.write( "For the definition of tangent \n" ); document.write( "Finally \n" ); document.write( "Therefore, as \n" ); document.write( " \n" ); document.write( "Still Algebra: \n" ); document.write( " \n" ); document.write( "Now we apply the sum identity of the tangent \n" ); document.write( " \n" ); document.write( "Known that \n" ); document.write( " \n" ); document.write( "Now let's apply the half angle formula for the tangent \n" ); document.write( " \n" ); document.write( "Again Algebra and provided that \n" ); document.write( " \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "and provided that \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "The first term cannot be zero for the previous condition, so the possible solution must satisfy: \n" ); document.write( " \n" ); document.write( "that happens when \n" ); document.write( "The general solution would be \n" ); document.write( "\n" ); document.write( "Eventually we check the solution that is that in case of a right/isosceles triangle the relation BC=AB+AI is satisfied. \n" ); document.write( "With the same notation above: \n" ); document.write( " \n" ); document.write( "BH is such that \n" ); document.write( "As \n" ); document.write( "But \n" ); document.write( "So \n" ); document.write( "Quod Demonstrandum Erat \n" ); document.write( " |