document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=803276>Question 803276</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have figured out how to find the probability when given P, but the q is now confusing me. I have tried a few different ways and I have three formulas in front of me. Very confused-please help! I am also able to see that the answer is \" 0.0818\" with no clue how they got to that point.\r<BR>\n" );
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document.write( "Assume that a procedure yields a binomial distribution with a trial repeated n=13  times. Find the probability of x=5  successes given the probability  q=0.42 of failure on a single trial.<BR>\n" );
document.write( "P(X=5)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484258 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484258\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the binomial probability formula,<BR>\n" );
document.write( "(1) P(x=5) = (n!/(n-x)!/x!)*(p^x)*(q^(n-x))<BR>\n" );
document.write( "where<BR>\n" );
document.write( "q = 0.42<BR>\n" );
document.write( "p = 1 - q = 0.58<BR>\n" );
document.write( "n = 13<BR>\n" );
document.write( "x = 5<BR>\n" );
document.write( "Place the varible values into (1) and get<BR>\n" );
document.write( "(2) P(x=5) = (13!/8!/5!)*(0.58^5)*(0.42^8) or<BR>\n" );
document.write( "(3) P(x=5) = 1287*(0.58^5)*(0.42^8) or<BR>\n" );
document.write( "(40 P(x=5) = 0.0818 </SPAN>\n" );
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