document.write( "Question 447446: If log-a 4=1.386, log-a 5=1.609, and log-a 6=1.792 find the following:\r
\n" ); document.write( "\n" ); document.write( "log-a 2/3
\n" ); document.write( "log-a 20 \n" ); document.write( "
Algebra.Com's Answer #484233 by algebrahelp101(11)\"\" \"About 
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Given: log-a 4=1.386, we have:
\n" ); document.write( "log-a 2^2=1.386
\n" ); document.write( "2*log-a 2=1.386
\n" ); document.write( "log-a 2=1.386/2 -> log-a 2=0.693
\n" ); document.write( "Given log-a 5=1.609 -> log-a 5=1.609 (5 is prime)
\n" ); document.write( "Given log-a 6=1.792, we have:
\n" ); document.write( "log-a (2*3)=1.792
\n" ); document.write( "log-a 2 + log-a 3=1.792
\n" ); document.write( "log-a 3 = 1.792 - log-a 2
\n" ); document.write( "log-a 3 = 1.792 - 0.693 -> log-a 3 = 1.099
\n" ); document.write( "Find:
\n" ); document.write( "log-a 2/3 = log-a 2 - log-a 3
\n" ); document.write( "= 0.693 - 1.099
\n" ); document.write( "= -0.406
\n" ); document.write( "Find:
\n" ); document.write( "log-a 20 = log-a (4*5)
\n" ); document.write( "= log-a 4 + log-a 5
\n" ); document.write( "= log-a 2^2 + log-a 5
\n" ); document.write( "= 2*log-a 2 + log-a 5
\n" ); document.write( "= 2*0.693 + 1.609
\n" ); document.write( "= 2.995\r
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