document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=803257>Question 803257</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two planes left at the same time from airports 4500 miles apart and flew toward each other. In five hours they passed each other. The rate of the faster plane is twice the rate of the slower plane. Find the rate of each plane. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484230 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484230\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two planes left at the same time from airports 4500 miles apart and flew toward each other. In five hours they passed each other. The rate of the faster plane is twice the rate of the slower plane. Find the rate of each plane.<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=rate of slower plane<BR>\n" );
document.write( "2x=rate of faster plane<BR>\n" );
document.write( "distance=rare*travel time<BR>\n" );
document.write( "...<BR>\n" );
document.write( "5x+5(2x)=4500<BR>\n" );
document.write( "15x=4500<BR>\n" );
document.write( "x=300<BR>\n" );
document.write( "2x=600<BR>\n" );
document.write( "rate of slower plane=300mph<BR>\n" );
document.write( "rate of faster plane=600mph </SPAN>\n" );
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