document.write( "Question 8863: I'm so lost on this one. I do remember the order of operations, however this is a very complex formula, I hope I type it well enough or it'll get a completely different meaning and answer. Here goes:
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\n" ); document.write( "Looks like it came through correctly, please help...
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Algebra.Com's Answer #4842 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
This is SO INTIMIDATING!! It probably is really easy if you dare to look at it. \r
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\n" ); document.write( "\n" ); document.write( "First, simplify the numerator at the very top: 3*8 is 24, and add 11, which is 35.\r
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\n" ); document.write( "\n" ); document.write( "Second, in the middle, go ahead and multiply the (2t)*(3*8) which is 2t*24 or 48t. Then simplify the fraction that follows, which is \"%284t%5E2%29%2Ft\" and simplifies to 4t. This combines with the 48t, so 48t - 4t = 44t.\r
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\n" ); document.write( "\n" ); document.write( "Third, the denominator at the bottom likewise simplifies, with the 3 and -3 subtracting out, to \"t%2F%282t%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "The net result is this:\"35%2F%2844t%29\" divided by \"t%2F%282t%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Invert and multiply:
\n" ); document.write( "\"%2835%2F%2844t%29%29+%2A+%28+%282t%5E2%29%2Ft%29\"\r
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\n" ); document.write( "\n" ); document.write( "As you can see the t's all divide out, the 2 divides out, and you are left with \"35%2F22\".\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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\n" ); document.write( "\n" ); document.write( "P.S. Congratulations on writing that equation in an algebra.com formatted equation!! You must be a math teacher???\r
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