document.write( "Question 803219: Graphing Nonlinear Functions:\r
\n" ); document.write( "\n" ); document.write( "f(x)=2(x+1)^2\r
\n" ); document.write( "\n" ); document.write( "The only mark on the graph I could accurately come up with was 2(0+1)^2=2 for the middle point of the Parabola. When I try to create symetry but putting in 1,2,-1,-2 I end up all over the place. What am I doing wrong? \n" ); document.write( "

Algebra.Com's Answer #484190 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
It looks like $\"+x+=+-1+\"$ would be at the
\n" ); document.write( "vertex of the parabola because if I go equally in
\n" ); document.write( "the (+) and (-) directions from $\"+x+=+-1+\"$ ,
\n" ); document.write( "I get the same $\"+f%28x%29+\"$
\n" ); document.write( " $\"+x+=+-2+\"$
\n" ); document.write( " $\"+f%28x%29+=+2+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+x+=+0+\"$
\n" ); document.write( " $\"+f%28x%29+=+2+\"$
\n" ); document.write( "------------
\n" ); document.write( " $\"+x+=+-3+\"$
\n" ); document.write( " $\"+f%28x%29+=+8+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+x+=+1+\"$
\n" ); document.write( " $\"+f%28x%29+=+8+\"$
\n" ); document.write( "------------
\n" ); document.write( "etc.
\n" ); document.write( "So, the vertex is at $\"+x+=+-1+\"$ , $\"+f%28x%29+=+0+\"$
\n" ); document.write( "Here's the plot:
\n" ); document.write( " $\"+graph%28+400%2C+400%2C+-5%2C+5%2C+-5%2C+5%2C+2%2A%28+x%2B1+%29%5E2+%29+\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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