document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=803066>Question 803066</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Problem 1<BR>\n" );
document.write( "Separate 102 into two parts such that the larger part divided by the smaller part will give a quotient of 6 and a remainder of 11.\r<BR>\n" );
document.write( "\n" );
document.write( "Problem 2<BR>\n" );
document.write( "A man invested part of P10, 000 at 6% and the rest at 7%. The annual income from the 7% investment was P35 less than seven times the annual income from the 6 % investment. How much did he invest at each rate?\r<BR>\n" );
document.write( "\n" );
document.write( "Problem 3<BR>\n" );
document.write( "A tank can fill by one pipe stream in 5 hours and by another pipe stream in 4 hours. It can be emptied ba third pipe stream in 7 hours. How long will it take to fill the tank if all pipes are open?\r<BR>\n" );
document.write( "\n" );
document.write( "Problem 4<BR>\n" );
document.write( "A retailer wishes to mix rice selling at P12 per kilogram with rice selling at P 15 per kilogram so as to make a mixture of 48 kilograms worth P13 per kilogram. How many kilograms of each kind must be used?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484107 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Most of those are uniform rates problems, but I will help with your \"102 two parts\" problem.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x and y two numbers.  Assuming <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2By=102 ALIGN=MIDDLE  ALT=\"x%2By=102\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and assuming <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%3Ex ALIGN=MIDDLE  ALT=\"y%3Ex\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%2Fx=6%2B11%2Fx ALIGN=MIDDLE  ALT=\"y%2Fx=6%2B11%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The system to solve is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2By=102 ALIGN=MIDDLE  ALT=\"x%2By=102\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%2Fx=6%2B11%2Fx ALIGN=MIDDLE  ALT=\"y%2Fx=6%2B11%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  In second equation with the quotient & remainder, multiply both sides by x:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=6x%2B11 ALIGN=MIDDLE  ALT=\"y=6x%2B11\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and then try substituting this for y in the 102 sum equation:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B6x%2B11=102 ALIGN=MIDDLE  ALT=\"x%2B6x%2B11=102\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and you can continue from there?  Solve for x first? </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );