document.write( "Question 802717: The oldest child in a family is 5 years older than her brother. The mother is 1 year younger than twice the sum of her kid's ages. The father's age equals the mother's age plus the son's age. If the sum of all 4 ages is three times a prime number and the mom was younger than 50 when she had her 2nd child how old is the daughter? \n" ); document.write( "
Algebra.Com's Answer #484103 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let d = age of the daughter \n" ); document.write( "let b = age of the brother \n" ); document.write( "let m = age of the mother \n" ); document.write( "let f = age of the father \n" ); document.write( "let p = prime number referred to in the problem \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "The oldest child in a family is 5 years older than her brother. \n" ); document.write( "d = b + 5 \n" ); document.write( ": \n" ); document.write( " The mother is 1 year younger than twice the sum of her kid's ages. \n" ); document.write( "m = 2(d+b) - 1 \n" ); document.write( "m = 2d + 2b - 1 \n" ); document.write( ": \n" ); document.write( " The father's age equals the mother's age plus the son's age. \n" ); document.write( "f = m + b \n" ); document.write( ": \n" ); document.write( " If the sum of all 4 ages is three times a prime number \n" ); document.write( "d + b + m + f = 3p \n" ); document.write( "replace m with (2d+2b-1) \n" ); document.write( "d + b + (2d+2b-1) + f = 3p \n" ); document.write( "3d + 3b + f = 3p+1 \n" ); document.write( "Replace f with (m+b) \n" ); document.write( "3d + 3b + (m+b) = 3p+1 \n" ); document.write( "3d + 4b + m = 3p+1 \n" ); document.write( "replace m with (2d+2b-1) again \n" ); document.write( "3d + 4b + (2d+2b-1) = 3p+1 \n" ); document.write( "5d + 6b = 3p + 1 + 1 \n" ); document.write( "5d + 6b = 3p + 2 \n" ); document.write( "Replace d with (b+5) \n" ); document.write( "5(b+5) + 6b = 3p + 2 \n" ); document.write( "5b + 25 + 6b = 3p + 2 \n" ); document.write( "11b = 3p + 2 - 25 \n" ); document.write( "11b = 3p - 23 \n" ); document.write( "rearrange to \n" ); document.write( "3p = 11b + 23 \n" ); document.write( "divide by 3 \n" ); document.write( "p = \n" ); document.write( "Find a value for b that makes p a prime number \n" ); document.write( "when b = 8, (brother's age) and p = 37, sum of all 4 ages: 3*37 = 111 \n" ); document.write( "then \n" ); document.write( "d = 8+5 \n" ); document.write( "d = 13 yrs, daughter's age \n" ); document.write( "m = 2(8+13)) - 1 \n" ); document.write( "m = 41 yrs is Mom's age \n" ); document.write( "f = 41 + 8 \n" ); document.write( "f = 49 yrs is Dad's age \n" ); document.write( ": \n" ); document.write( "See if that adds up 8 + 13 + 41 + 49 = 111 \n" ); document.write( ": \n" ); document.write( "Sorry about the first attempt, got hung up on 5th grade math!\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |