document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=802861>Question 802861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the slope of the line which contains (2/3,-4)and passes through the origin? Please show me the steps to solving this. Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484089 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> As the line passes thro' the origin<BR>\n" );
document.write( "this gives you another set of coordinates,<BR>\n" );
document.write( "(0,0)<BR>\n" );
document.write( "Using the gradient (slope) equation:<BR>\n" );
document.write( "y2 - y1/x2 - x1<BR>\n" );
document.write( "-4 - 0/2/3 - 0<BR>\n" );
document.write( "-4/2/3<BR>\n" );
document.write( "Slope = -6<BR>\n" );
document.write( "Using y = mx + c<BR>\n" );
document.write( "-4 = -6(2/3) + c<BR>\n" );
document.write( "-4 = -4 + c<BR>\n" );
document.write( "c = 0<BR>\n" );
document.write( "Equation = y = -6x<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );