document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=802970>Question 802970</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A school tuck shop made 2 orders for large and small pies pies. The first order of 40 small and40 large pies came to $154 and the second order of 50 small and 30 large pies was $144.50. <BR>\n" );
document.write( "A define the variables you will use to solve this question<BR>\n" );
document.write( "B form two equations that can be solved simultaneously<BR>\n" );
document.write( "C prove the equations <BR>\n" );
document.write( "Can you please show me all the workings, I just can't get it.. <BR>\n" );
document.write( "Thanks <BR>\n" );
document.write( "Deanna<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484082 by </B><A HREF=/tutors/aboutme.mpl?userid=thejackal><B>thejackal(72)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thejackal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=thejackal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> very simple\r<BR>\n" );
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document.write( "let the unit price of small and large pies be S and L respectively such that\r<BR>\n" );
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document.write( "1st order which was - 40S + 40L = $154<BR>\n" );
document.write( "2nd order which was - 50S + 30L = $144.50\r<BR>\n" );
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document.write( "we want to know what the unit price is for small and large pies, to do this<BR>\n" );
document.write( "solve simultaneously \r<BR>\n" );
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document.write( "40S + 40L = 154<BR>\n" );
document.write( "50S + 30L = 144.50\r<BR>\n" );
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document.write( "using either equation, express S in terms of L for example\r<BR>\n" );
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document.write( "50S = 144.5 - 30L<BR>\n" );
document.write( "  S = 2.89 - 3/5L\r<BR>\n" );
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document.write( "use the equation for S in the first equation \r<BR>\n" );
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document.write( "40 (2.89 - 3/5L) + 40L = 154<BR>\n" );
document.write( "simplify<BR>\n" );
document.write( "16 L = 38.4<BR>\n" );
document.write( "   L = 2.4\r<BR>\n" );
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document.write( "plug the value of L into the previous equation for S\r<BR>\n" );
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document.write( "S = 2.89 - 3/5(2.4)<BR>\n" );
document.write( "S = 1.45\r<BR>\n" );
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document.write( "prove it by using your answers in the original question\r<BR>\n" );
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document.write( "40(1.45) + 40(2.4) should be equal to 154\r<BR>\n" );
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