document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=802943>Question 802943</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boy's age is X years and his father is four times as old. Find the Father's age in Y years time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484058 by </B><A HREF=/tutors/aboutme.mpl?userid=thejackal><B>thejackal(72)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thejackal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=thejackal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484058\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The answer to this question is a function <BR>\n" );
document.write( "the fathers age is a function of X\r<BR>\n" );
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document.write( "such that f(x) = 4x\r<BR>\n" );
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document.write( "so if the present age of the boy is X then in in Y years time the boys new age x will be x + y\r<BR>\n" );
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document.write( "thus the fathers age will be expressed as 4(x+y)  </SPAN>\n" );
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