document.write( "Question 802949: A car leaves for Sacramento for Los Angeles traveling 54 mi/hr. A half hour later another car leaves Sacramento for Los Angeles traveling 64 mi/hr. How long after the second car leaves will it pass the first car? \n" ); document.write( "
Algebra.Com's Answer #484053 by mananth(16946)\"\" \"About 
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A car leaves for Sacramento for Los Angeles traveling 54 mi/hr. A half hour later another car leaves Sacramento for Los Angeles traveling 64 mi/hr. How long after the second car leaves will it pass the first car?\r
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\n" ); document.write( "\n" ); document.write( "Let the distance they meet at from Sacramento be x\r
\n" ); document.write( "\n" ); document.write( "Car I t= x/54\r
\n" ); document.write( "\n" ); document.write( "Car II t= x/64\r
\n" ); document.write( "\n" ); document.write( "Time taken by Car I - time taken by Car II = 1/2\r
\n" ); document.write( "\n" ); document.write( "x/54-x/64=1/2\r
\n" ); document.write( "\n" ); document.write( "64x-54x=54*64/2\r
\n" ); document.write( "\n" ); document.write( "10x=54*32
\n" ); document.write( "10x = 1728
\n" ); document.write( "/10
\n" ); document.write( "x=172.8\r
\n" ); document.write( "\n" ); document.write( "t= d/r\r
\n" ); document.write( "\n" ); document.write( "t= 172.8/64
\n" ); document.write( "=2.7 hours\r
\n" ); document.write( "\n" ); document.write( "Car II will meet after 2.7 hours
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