document.write( "Question 802659: There were 310 phones and tabs for sale in a shop.All the phones in the shop cost $2484 more than all the tabs. After 1/3 of the phones and 10/11 of the tabs were sold, there were thrice as many phones as tabs left.If each phone cost $714 more than each tab,how much did each tab cost? \n" ); document.write( "
Algebra.Com's Answer #484050 by KMST(5328)\"\" \"About 
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\"x\"= number of phones
\n" ); document.write( "\"y\"= number of tabs
\n" ); document.write( "We use the information given to set a system of linear equations to find \"x\" and \"y\".
\n" ); document.write( "\"x%2By=310\"
\n" ); document.write( "After 1/3 of the phones were sold, there are \"x-%281%2F3%29x=%282%2F3%29x\" left.
\n" ); document.write( "After 10/11 of the tabs were sold, there are \"y-%2810%2F11%29y=%281%2F11%29y\" left.
\n" ); document.write( "Since \"%282%2F3%29x\" is thrice as many as \"%281%2F11%29y\",
\n" ); document.write( "\"%282%2F3%29x=3%2A%281%2F11%29y\"
\n" ); document.write( "\"%282%2F3%29x=%283%2F11%29y\"
\n" ); document.write( "\"33%2A%282%2F3%29x=33%2A%283%2F11%29y\"
\n" ); document.write( "\"22x=9y\"
\n" ); document.write( "\"y=%2822%2F9%29x\"
\n" ); document.write( "So \"x%2B%2822%2F9%29x=310\"-->\"%2831%2F9%29x=310\"-->\"x=310%2A9%2F31\"-->\"x=90\"
\n" ); document.write( "So \"y=%2822%2F9%2990\"-->\"y=220\"
\n" ); document.write( "
\n" ); document.write( "\"t\"= price of a tab, in $
\n" ); document.write( "so \"t%2B714\"= price of a phone, in $
\n" ); document.write( "\"90%28t%2B714%29\"= how much all the phones originally in the shop cost
\n" ); document.write( "$\"220t%2B2484%29\"= $2484 more than what all the tabs originally in the shop cost
\n" ); document.write( "\"220t%2B2484=90%28t%2B714%29\"
\n" ); document.write( "\"220t%2B2484=90t%2B64260\"
\n" ); document.write( "\"220t-90t=64260-2484\"
\n" ); document.write( "\"130t=31776\"
\n" ); document.write( "\"t=31776%2F130\" --> \"highlight%28t=475.2%29\"
\n" ); document.write( "
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