document.write( "Question 802647: The area of a rectangle is 64 square centimeters.Its perimeter is 40 centimeters.What are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #484041 by ankor@dixie-net.com(22740)\"\" \"About 
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The area of a rectangle is 64 square centimeters.
\n" ); document.write( "L * W = 64
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\n" ); document.write( "Its perimeter is 40 centimeters.
\n" ); document.write( "2L + 2W = 40
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "L + W = 20
\n" ); document.write( "L = (20-W)
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\n" ); document.write( "In the area equation, replace L with (20-W)
\n" ); document.write( "W(20-W) = 64
\n" ); document.write( "20W - W^2 = 64
\n" ); document.write( "arrange as a quadratic equation on the right
\n" ); document.write( "0 = W^2 - 20W + 64
\n" ); document.write( "Factors to
\n" ); document.write( "(W-4)(w-16) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "W = 4, then L = 16
\n" ); document.write( "or
\n" ); document.write( "W = 16, then L = 4
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\n" ); document.write( "Check the perimeter: 2(16) + 2(4) = 40\r
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