document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=802898>Question 802898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Perpendicular to the graph of 5x-3y=9 and passes through the orgin </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #484040 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=484040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x-3y=9\r<BR>\n" );
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document.write( "3y=5x-9\r<BR>\n" );
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document.write( "y=(5/3)x-3\r<BR>\n" );
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document.write( "slope = (5/3)\r<BR>\n" );
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document.write( "passing through (0,0) and perpendicular to the above line\r<BR>\n" );
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document.write( "so slope will be negative reciprocal = (-3/5)\r<BR>\n" );
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document.write( "The equation is\r<BR>\n" );
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document.write( "(y-0)=(-3/5)(x-0)\r<BR>\n" );
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document.write( "y= -3/5 x </SPAN>\n" );
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