document.write( "Question 802905: 6y^2 - 24 = 0\r
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Algebra.Com's Answer #484038 by mananth(16946)\"\" \"About 
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\"6y%5E2-24=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"6%28y%5E2-4%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"6%28y%2B2%29%28y-2%29=0\"\r
\n" ); document.write( "\n" ); document.write( "Either (y+2) = 0
\n" ); document.write( "OR (y-2) =0\r
\n" ); document.write( "\n" ); document.write( "so y= +/- 2
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