document.write( "Question 802814: An engineer is designing a parabolic arch. The arch must be 15m high and 6m wide at a height of 8m. Determine a quadratic function that satisfies these conditions and the width of the arch at its base.\r
\n" ); document.write( "\n" ); document.write( "This is what I have so far:\r
\n" ); document.write( "\n" ); document.write( "vertex (x,15)
\n" ); document.write( "passes through point (6,8)\r
\n" ); document.write( "\n" ); document.write( "h(w)= a(x-h)^2+15\r
\n" ); document.write( "\n" ); document.write( "Can you help me with the rest.\r
\n" ); document.write( "\n" ); document.write( "Thanks
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Algebra.Com's Answer #484023 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
If it passes through point (6,8), it would need to pass through (0,8); the vertex will be at (3,15), and the base will be from a point (-b,0), to a point (6+b,0).
\n" ); document.write( "That makes it complicated.
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\n" ); document.write( "Let's put the origin (0,0) at a point on the ground, directly below the vertex.
\n" ); document.write( "We make the line that passes through the feet of the arch the x-axis.
\n" ); document.write( "We call the vertical axis of symmetry of the arch our y-axis.
\n" ); document.write( "We measure x (the horizontal distance to the origin) in meters,
\n" ); document.write( "and y or h(x) (the height above the ground) also in meters.
\n" ); document.write( "\"h%28x%29=ax%5E2%2B15\" is our equation
\n" ); document.write( "The vertex will be (0,15).
\n" ); document.write( "The points at a height of 8 meters will be (-3,8) and (3,8), so that the arch width at that height is the (horizontal distance from (-3,8) to 3,8, which is 6.
\n" ); document.write( "Substituting the coordinates of (3,8), we get
\n" ); document.write( "\"8=+a%2A3%5E3%2B15\"
\n" ); document.write( "\"8=9a%2B15\"
\n" ); document.write( "\"8-15=9a\"
\n" ); document.write( "\"9a=-7\"
\n" ); document.write( "\"a=-7%2F9\"
\n" ); document.write( "\"highlight%28h%28x%29=%28-7%2F9%29x%5E2%2B15%29\"
\n" ); document.write( "At the base, \"h%28x%29=0\" and
\n" ); document.write( "\"%28-7%2F9%29x%5E2%2B15=0\" needs to be solved
\n" ); document.write( "\"%28-9%2F7%29%28-7%2F9%29x%5E2=-15%28-9%2F7%29\"
\n" ); document.write( "\"x%5E2=15%2A9%2F7\"
\n" ); document.write( "\"x%5E2=135%2F7\"
\n" ); document.write( "The feet of the arch are at \"x=-sqrt%28135%2F7%29\" and \"x=sqrt%28135%2F7%29\"
\n" ); document.write( "and the width at the base is
\n" ); document.write( "\"sqrt%28135%2F7%29-%28-sqrt%28135%2F7%29%29=2sqrt%28135%2F7%29\"= approx. 7.75 meters
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