document.write( "Question 802679: x^2/3-y^2/3 / x^1/3 + y^1/3 \n" ); document.write( "

Algebra.Com's Answer #483990 by htmentor(1343) $\"\"$ $\"About$

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If we make the substitution w = x^1/3, z = y^1/3, we can eliminate the fractional exponents
\n" ); document.write( "(x^2/3 - y^2/3)/(x^1/3 + y^1/3) -> (w^2 - z^2)/(w + z)
\n" ); document.write( "The numerator can be factored as (w+z)(w-z):
\n" ); document.write( "(w+z)(w-z)/(w+z) = w-z
\n" ); document.write( "Substituting back the original variables gives x^1/3 - y^1/3 \n" ); document.write( "

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