document.write( "Question 802744: The length of a rectangle is 3 feet more than 4 times the width. If the area is 45 square feet, find the width and the length.
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Algebra.Com's Answer #483985 by Cromlix(4381)\"\" \"About 
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Width = x
\n" ); document.write( "Length = 3 + 4x
\n" ); document.write( "Area = width*length
\n" ); document.write( "45 = x(3 + 4x)
\n" ); document.write( "45 = 3x + 4x^2
\n" ); document.write( "4x^2 + 3x - 45 = 0
\n" ); document.write( "(4x + 15)(x - 3) = 0
\n" ); document.write( "4x + 15 = 0
\n" ); document.write( "x = -15/4 (no answer as x<0)
\n" ); document.write( "x - 3 = 0
\n" ); document.write( "x = 3
\n" ); document.write( "Width = 3 feet
\n" ); document.write( "Length = 15 feet
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-) \n" ); document.write( "
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