document.write( "Question 802663: Divide 72 in to two parts so that the larger part exceeds the smaller by 12 , find the both parts. \n" ); document.write( "
Algebra.Com's Answer #483967 by mananth(16946)    You can put this solution on YOUR website! if one part is x then other part will be x+12\r \n" ); document.write( "\n" ); document.write( "Their sum = 72\r \n" ); document.write( "\n" ); document.write( "x+x+12=72\r \n" ); document.write( "\n" ); document.write( "2x+12=72\r \n" ); document.write( "\n" ); document.write( "2x+12-12=72-12 \n" ); document.write( "2x=60 \n" ); document.write( "/2 \n" ); document.write( "2x/2 = 60/2\r \n" ); document.write( "\n" ); document.write( "x=30\r \n" ); document.write( "\n" ); document.write( "One part is 30 so the balance is 42 the other part \n" ); document.write( "  |