document.write( "Question 802591: Triangle QRS has vertices Q(-4,-1)R(-1,3)S(5,-3).
\n" ); document.write( "Write the equation of the line containing the altitude through point R.
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Algebra.Com's Answer #483947 by KMST(5328)\"\" \"About 
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The altitude through point R is the line that passes through R and is perpendicular to the line QS.
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\n" ); document.write( "The slope of the line QS is
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\n" ); document.write( "The product of the slopes of two perpendicular lines is \"-1\".
\n" ); document.write( "So the slope of a line perpendicular to QS is
\n" ); document.write( "\"m=%28-1%29%2F%28%28-2%2F9%29%29=%28-1%29%2A%28-9%2F2%29=9%2F2\"
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\n" ); document.write( "A point, \"+%22%28+x+%2C+y+%29%22+\", on a line with slope \"m\" that passes through \"+P+%28+x%5BP%5D+%2C+y%5BP%5D+%29+\" satisfies
\n" ); document.write( "\"m=%28y-y%5BP%5D%29%2F%28x-x%5BP%5D%29\" <--> \"y-y%5BP%5D=m%28x-x%5BP%5D%29\"
\n" ); document.write( "(The equation \"y-y%5BP%5D=m%28x-x%5BP%5D%29\" is called the point-slope form of the equation of the line).
\n" ); document.write( "Applying that to point \"+R+%28+-1+%2C+3+%29+\" and slope \"m=9%2F2\" we get
\n" ); document.write( "\"y-3=%289%2F2%29%28x-%28-1%29%29\" --> \"y-3=%289%2F2%29%28x%2B1%29\" --> \"y-3=%289%2F2%29x%2B9%2F2\" --> \"y=%289%2F2%29x%2B9%2F2%2B3\" --> \"highlight%28y=%289%2F2%29x%2B15%2F2%29\"
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