document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=802602>Question 802602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Good day, <BR>\n" );
document.write( "My question is that I could use some assistance with is (thanks in advance!):\r<BR>\n" );
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document.write( "Given that theta = 17pi/6 use the period of the functions as well as the special angles to find the exact values (does this mean radians?) of the sin, cos and tan of theta.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483932 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that theta = 17pi/6, find the exact values of the sin, cos and tan of theta.<BR>\n" );
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document.write( "What you need to know is the reference angle of given angle theta=17&#960;/6, and which quadrant it is in.<BR>\n" );
document.write( "17&#960;/6 is like rotating counter-clockwise around the unit circle 16&#960; plus an additional &#960;/6, which places the reference angle of &#960;/6 in quadrant I.<BR>\n" );
document.write( "sin(17&#960;/6)=sin(&#960;/6)=1/2<BR>\n" );
document.write( "cos(17&#960;/6)=cos(&#960;/6)=&#8730;3/2<BR>\n" );
document.write( "tan(17&#960;/6)=tan(&#960;/6)=sin/cos=1/&#8730;3=&#8730;3/3 </SPAN>\n" );
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