document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=802549>Question 802549</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the numerator and denominator of a fraction is 12. If the denominator is increased by 3, the fraction Becomes ½. Find the fraction </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483923 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let numerator be x<BR>\n" );
document.write( "denominator be y\r<BR>\n" );
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document.write( "x+y=12..................(1)\r<BR>\n" );
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document.write( "(x+3)/y = 1/2\r<BR>\n" );
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document.write( "2(x+3)=y\r<BR>\n" );
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document.write( "2x+6 =y\r<BR>\n" );
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document.write( "substitute y in (1)\r<BR>\n" );
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document.write( "x+2x+6=12\r<BR>\n" );
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document.write( "3x+6=12<BR>\n" );
document.write( "3x=12-6<BR>\n" );
document.write( "3x=6<BR>\n" );
document.write( "/3<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "y=10\r<BR>\n" );
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document.write( "The fraction is 2/10 </SPAN>\n" );
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