document.write( "Question 802532: find (x,y)\r
\n" ); document.write( "\n" ); document.write( "y=1/3x + 5/2
\n" ); document.write( "x-4y=-8\r
\n" ); document.write( "\n" ); document.write( "I keep getting (-6, 9/2)
\n" ); document.write( "But the answer sheet shows (9, 4)....
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Algebra.Com's Answer #483916 by mananth(16946)\"\" \"About 
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y=1/3x + 5/2\r
\n" ); document.write( "\n" ); document.write( "multiply by 6\r
\n" ); document.write( "\n" ); document.write( "6y=2x+15
\n" ); document.write( "2x-6y=-15...........................(1)
\n" ); document.write( "x-4y=-8.............................(2)\r
\n" ); document.write( "\n" ); document.write( "solve (1) & (2)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2 x -6 y = -15 .............1
\n" ); document.write( "Total value
\n" ); document.write( "1 x -4 y = -8 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by 2
\n" ); document.write( "Multiply (2) by -3
\n" ); document.write( "4 x -12 y = -30
\n" ); document.write( "-3 x + 12 y = 24
\n" ); document.write( "Add the two equations
\n" ); document.write( "1 x = -6
\n" ); document.write( "/ 1
\n" ); document.write( "x = -6
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "2 x -6 y = -15
\n" ); document.write( "-12 -6 y = -15
\n" ); document.write( " -6 y = -15 + 12
\n" ); document.write( " -6 y = -3
\n" ); document.write( " y = 1/2
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