document.write( "Question 802493: How much of a 20% acid solution should be added to 10 L of a 60% acid solution to make a 25% acid solution? \n" ); document.write( "
Algebra.Com's Answer #483905 by mananth(16946)\"\" \"About 
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--- percent ---------------- Amount
\n" ); document.write( "Solution I 60 ---------------- 10 liters
\n" ); document.write( "solution II 20 ---------------- x liters
\n" ); document.write( "Mixture 25 ---------------- 10 + x liters
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\n" ); document.write( "60 * 10 + 20 x = 25 ( 10 + x )
\n" ); document.write( "600 + 20 x = 250 + 25 x
\n" ); document.write( "20 x -25 x = -600 + 250
\n" ); document.write( "-5 x = -350
\n" ); document.write( "/ -5
\n" ); document.write( "x = 70 liters solution II
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\n" ); document.write( "m.ananth@hotmail.ca
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