document.write( "Question 802463: A chemist wants to make 52 mL of a 17% acid solution by mixing a 11% acid solution and an 19% acid solution. How many milliliters of each solution should the chemist use? \n" ); document.write( "
Algebra.Com's Answer #483904 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Acid solution I 19.00% ---------------- x ml
\n" ); document.write( "Acid solution II 11.00% ------ 52 - x ml
\n" ); document.write( "Mixture 17.00% ---------------- 52
\n" ); document.write( "Total 52 ml
\n" ); document.write( "19.00% x + 11.00% ( 52 - x ) = 17.00% * 52
\n" ); document.write( "19 x + 11 ( 52 - x ) = 884
\n" ); document.write( "19 x + 572 - 11 x = 884
\n" ); document.write( "19 x - 11 x = 884 - -572
\n" ); document.write( "8 x = 312
\n" ); document.write( "/ 8
\n" ); document.write( " x = 39 ml 19.00% Acid solution I
\n" ); document.write( " 13 ml 11.00% Acid solution II
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\n" ); document.write( "m.ananth@hotmail.ca
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