document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=802271>Question 802271</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pipe of thickness 1/2cm has an external diameter of 12 cm. Find the volume of 2.4m of pipe. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483830 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let r = inside radius of the pipe, cm<BR>\n" );
document.write( "Let h = height (length) of the pipe, cm<BR>\n" );
document.write( "Let B = inside area of the end of the pipe, cm^2<BR>\n" );
document.write( "Let V = the volume of the pipe, cm^3<BR>\n" );
document.write( "Use the formula<BR>\n" );
document.write( "(1) V = B*h or<BR>\n" );
document.write( "(2) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+%28pi%2Ar%5E2%29%2Ah ALIGN=MIDDLE  ALT=\"V+=+%28pi%2Ar%5E2%29%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The inside diameter is the outside diameter of 12cm minus twice the thickness, 0.5cm, of the pipe. The inside radius is one half of the inside diameter or<BR>\n" );
document.write( "(3) r = (12-2*0.5)/2 or<BR>\n" );
document.write( "(4) r = (12-1)/2 or<BR>\n" );
document.write( "(5) r = 11/2 or<BR>\n" );
document.write( "(6) r = 5.5<BR>\n" );
document.write( "The area of the pipe's cross-section is<BR>\n" );
document.write( "(7) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=B+=+pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"B+=+pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > or<BR>\n" );
document.write( "(8) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=B+=+pi%2A5.5%5E2 ALIGN=MIDDLE  ALT=\"B+=+pi%2A5.5%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > or<BR>\n" );
document.write( "(9) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=B+=+pi%2A30.25 ALIGN=MIDDLE  ALT=\"B+=+pi%2A30.25\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The height, h, of the pipe is the same as the length or 2.4m, which converts to 240cm (all length units must be the same). Substituting B and h into (1) yields<BR>\n" );
document.write( "(10) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+pi%2A30.25%2A240 ALIGN=MIDDLE  ALT=\"V+=+pi%2A30.25%2A240\"   DISABLED_style= \"max-width:90%; height:auto;\" > or<BR>\n" );
document.write( "(11) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+pi%2A7260+cm%5E3 ALIGN=MIDDLE  ALT=\"V+=+pi%2A7260+cm%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" > or<BR>\n" );
document.write( "(12) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+22808cm%5E3 ALIGN=MIDDLE  ALT=\"V+=+22808cm%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" > or<BR>\n" );
document.write( "(13) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+0.0228m%5E3 ALIGN=MIDDLE  ALT=\"V+=+0.0228m%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );