document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=802181>Question 802181</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a quarter-pound bag of red pistachio nuts, some shells are too difficult to pry open by hand. Let the random variable X represent the number of pistachios in a randomly selected bag that cannot be opened by hand. The probability distribution for X is as follows: P(0)=0.500, P(1)=0.250, P(2)=0.100, P(3)=0.50, P(4)=0.075, P(5)=0.025<BR>\n" );
document.write( "Find the mean (average) number of nuts per bag that cannot be opened by hand. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483815 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483815\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The probability distribution for X is as follows: P(0)=0.500, P(1)=0.250, P(2)=0.100, P(3)=0.50, P(4)=0.075, P(5)=0.025<BR>\n" );
document.write( "Find the mean (average) number of nuts per bag that cannot be opened by hand.<BR>\n" );
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document.write( "mean = 0*0.5 + 1*0.25 + 2*0.10 + 3*0.5 + 4*0.075 + 5*0.025<BR>\n" );
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document.write( "Note: At least one of your posted probabilities is wrong.<BR>\n" );
document.write( "They add up to more than 1.  I suspect your p(3) = 0.50 is wrong.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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