document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8872>Question 8872</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do u find the area of a circle with the radius of 5 and 1/3 feet. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4838 by </B><A HREF=/tutors/aboutme.mpl?userid=mrduffner><B>mrduffner(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mrduffner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4838\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula for area of a circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"A+=+pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Let's plug in the radius.  We have <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+pi%2A%285%261%2F3%29%5E2 ALIGN=MIDDLE  ALT=\"A+=+pi%2A%285%261%2F3%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Then we square <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%261%2F3 ALIGN=MIDDLE  ALT=\"5%261%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >, making <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=28%264%2F9 ALIGN=MIDDLE  ALT=\"28%264%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  So the answer is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+28%264%2F9%2Api ALIGN=MIDDLE  ALT=\"A+=+28%264%2F9%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or approximately 89.36.  Hope this helps :) </SPAN>\n" );
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