document.write( "Question 68077: Here is another problem that I have posted within the past 2 days that I am having trouble with setting up. If someone could give me a little hint, I would appreciate it. Thanks.\r
\n" ); document.write( "\n" ); document.write( "A garden area is 30 ft long and 20 ft wide. A path of uniform width is set around the edge. If the remaining garden area is 400 ft2, what is the width of the path? Give your answer in decimal form, rounded to the nearest thousandth.
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Algebra.Com's Answer #48374 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
(30-2X)(20-2X)=400
\n" ); document.write( "600-40X-60X+4X^2=400
\n" ); document.write( "4X^2-100X+600-400=0
\n" ); document.write( "4X^2-100X+200=0
\n" ); document.write( "X^2-25X+50=0
\n" ); document.write( "using the quadratic equation we get
\n" ); document.write( "x=(-b+-sqrt[b^2-4ac])/2a
\n" ); document.write( "x=(25+-sqrt[-25^2-4*1*50])/2*1
\n" ); document.write( "x=(25+-sqrt625-200])/2
\n" ); document.write( "x=(25+-sqrt425)/2
\n" ); document.write( "x=(25+-20.6155)/2
\n" ); document.write( "x=(25+20.6155)/2
\n" ); document.write( "x=45.6155
\n" ); document.write( "x=(25-20.6155)/2
\n" ); document.write( "x=4.3845/2
\n" ); document.write( "x=2.192 answer for the width of the path.
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\n" ); document.write( "IF YOU DRAW A DIAGRAM OF THE PROBLEM (WHICH I ALWAYS RECOMMEND) YOU'LL SEE THAT THE RECTANGLE INSIDE ANOTHER RECTANGLE WITH THE OUTSIDE DIMENTIONS OF 20 & 30 FT
\n" ); document.write( "YOU'LL SEE THAT THE INNER RECTANGLE LENGTH IS 30 & 20 -2 TIMES THE BORDER (X) THUS THE TERMS 30-2X & 20-2X TO DESCRIBE THE INNER RECTANCLE.
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