document.write( "Question 68061: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #48367 by Earlsdon(6294)\"\" \"About 
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Let l = the length and W = the width of the rectangle. From the problem description, you can write:
\n" ); document.write( "\"L+=+2W%2B2\"
\n" ); document.write( "The perimeter, P, of a rectangle is given by:
\n" ); document.write( "\"P+=+2L+%2B+2W\" Substitute the L from above and P = 52 and solve for W.
\n" ); document.write( "\"52+=+2%282W%2B2%29+%2B+2W\"
\n" ); document.write( "\"52+=+4W%2B4+%2B+2w\"
\n" ); document.write( "\"52+=+6W%2B4\" Subtract 4 from both sides.
\n" ); document.write( "\"48+=+6W\" Divide both sides by 6.
\n" ); document.write( "\"8+=+W\"
\n" ); document.write( "The width is 8 cm
\n" ); document.write( "\"L+=+2W%2B2\"
\n" ); document.write( "\"L+=+2%288%29%2B2\"
\n" ); document.write( "\"L+=+16%2B2\"
\n" ); document.write( "\"L+=+18\"
\n" ); document.write( "The length is 18 cm\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "\"P+=+2L%2B2W\"
\n" ); document.write( "\"P+=+2%2818%29%2B2%288%29\"
\n" ); document.write( "\"P+=+36%2B16\"
\n" ); document.write( "\"P+=+52\"
\n" ); document.write( "
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