document.write( "Question 801871: We have recently started working with finding vertical asymptotes in class and I came across a problem in my homework that I am not sure how to approach. I have to find the vertical asymptote of g(x)=(2x-1)(x+2)/(2x+3)(3x-4) If you could please help me I would appreciate it. Thanks \n" ); document.write( "
Algebra.Com's Answer #483665 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
given: \"g%28x%29=%28%282x-1%29%28x%2B2%29%29%2F%28%282x%2B3%29%283x-4%29%29%29+\" \r
\n" ); document.write( "\n" ); document.write( "Vertical asymptote are zeros of denominator \"%28%282x%2B3%29%283x-4%29%29+\".\r
\n" ); document.write( "\n" ); document.write( "set the denominator to zero and solve for \"x\":\r
\n" ); document.write( "\n" ); document.write( "\"%282x%2B3%29%283x-4%29=0\" ....it will be equal to zero if either \"%282x%2B3%29=0\" or \"+%283x-4%29=0\"\r
\n" ); document.write( "\n" ); document.write( "if \"%282x%2B3%29=0\"=> \"2x+=-3\"=> \"x+=-3%2F2\"=> \"x+=-1.5\"\r
\n" ); document.write( "\n" ); document.write( "if \"+%283x-4%29=0\"=>\"+3x=4\"=>\"+x=4%2F3\"=>=>\"+x=1.33\"\r
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