document.write( "Question 801838: If 100 gallons of a 75% glycerin solution is made up by conbinding a 30% glycerin soulition with a 90% glycerin solution, how many gallons of each a solution must be used?? \n" ); document.write( "
Algebra.Com's Answer #483656 by wilft1(217)![]() ![]() You can put this solution on YOUR website! this will use 2 equations, solved using the addition method\r \n" ); document.write( "\n" ); document.write( "x + y = 100 \n" ); document.write( "30x + 90y = 75\r \n" ); document.write( "\n" ); document.write( "start by multiplying 100 x 75 and putting the answer in the bottom equation...\r \n" ); document.write( "\n" ); document.write( "x + y = 100 \n" ); document.write( "30x + 90y = 7500\r \n" ); document.write( "\n" ); document.write( "now, time to get rid of one of the variables, lets get rid of x by multiplying the top line by -30 and adding the two lines together...\r \n" ); document.write( "\n" ); document.write( "-30x - 30y = -3000 \n" ); document.write( "30x + 90y = 7500 \n" ); document.write( "................... \n" ); document.write( "60y = 4500\r \n" ); document.write( "\n" ); document.write( "divide both sides by 60\r \n" ); document.write( "\n" ); document.write( "y = 75\r \n" ); document.write( "\n" ); document.write( "now we know the value for y, lets plug that number into the original equation to find the value of x\r \n" ); document.write( "\n" ); document.write( "30x + 90(75) = 7500\r \n" ); document.write( "\n" ); document.write( "30x + 6750 = 7500\r \n" ); document.write( "\n" ); document.write( "subtract 6750 from both sides\r \n" ); document.write( "\n" ); document.write( "30x = 750\r \n" ); document.write( "\n" ); document.write( "divide both sides by 30\r \n" ); document.write( "\n" ); document.write( "x = 25\r \n" ); document.write( "\n" ); document.write( "so now we know, 25 gallons of 30% solution and 75 gallons of 90% solution. \n" ); document.write( " |