document.write( "Question 801751: A pharmacist has two vitamin-supplement powders. The first powder is 10% vitamin B1 and 30% vitamin B2. The second is 15% vitamin B1 and 20% vitamin B2. How many milligrams of each powder should the pharmacist use to make a mixture that contains 70 mg of vitamin B1 and 180 mg of vitamin B2? \n" ); document.write( "
Algebra.Com's Answer #483620 by josgarithmetic(39618)\"\" \"About 
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Let x = how many mg. of the first powder.
\n" ); document.write( "Let y = how many mg. the second powder.\r
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\n" ); document.write( "\n" ); document.write( "Accounting for vB1, \"0.10x%2B0.15y=70\"\r
\n" ); document.write( "\n" ); document.write( "Accounting for vB2, \"0.30x%2B0.20y=180\"\r
\n" ); document.write( "\n" ); document.write( "Look carefully how the units work to see that these equations make sense. The accountings are for milligrams of each B vitamin.\r
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\n" ); document.write( "\n" ); document.write( "Simplify the system, multiplying each equation by only 10:\r
\n" ); document.write( "\n" ); document.write( "\"x%2B%283%2F2%29y=700\" and \"3x%2B2y=1800\"
\n" ); document.write( "Integer coefficients would be more comfortable, so maybe try multiply the first equation by 2:\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B3y=1400\" and \"3x%2B2y=1800\"
\n" ); document.write( "Substitution seems like might be easier than trying elimination, so,\r
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\n" ); document.write( "\n" ); document.write( "\"2x=1400-3y\"
\n" ); document.write( "\"x=700-%283%2F2%29y\"
\n" ); document.write( "substitute into the other equation,
\n" ); document.write( "\"3%28700-%283%2F2%29y%29%2B2y=1800\"
\n" ); document.write( "\"2100-%289%2F2%29y%2B2y=1800\"
\n" ); document.write( "\"2100-1800=%289%2F2%29y-2y\"
\n" ); document.write( "\"%289%2F2-4%2F2%29y=300\"
\n" ); document.write( "\"%285%2F2%29y=300\"
\n" ); document.write( "\"y=300%282%2F5%29=highlight%28120%29\" milligrams of the second powder. Use any formula to find value for x.
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