document.write( "Question 68056: The sum of $127 was didvided among 3 people so that the second received $5 less than twice as much as the first, and the third received $2 more than the second. How much did each person receive? \n" ); document.write( "
Algebra.Com's Answer #48362 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The sum of $127 was didvided among 3 people so that the second received $5 less than twice as much as the first, and the third received $2 more than the second. How much did each person receive? \n" ); document.write( "--------- \n" ); document.write( "Let the amount the 1st received be x dollars. \n" ); document.write( "Then 2nd person received 2x-5 dollars. \n" ); document.write( "And 3rd person received 2x-5+2 = 2x-3 dollars. \n" ); document.write( "------------------- \n" ); document.write( "EQuATION: \n" ); document.write( "Total dollars was 127 \n" ); document.write( "x+2x-5+2x-3 = 127 \n" ); document.write( "5x-8=127 \n" ); document.write( "5x=135 \n" ); document.write( "x=27 dollars for 1st person \n" ); document.write( "2x-5=2*27-5=49 dollars for 2nd person \n" ); document.write( "2x-3=2*27-3= 51 dollars \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |