document.write( "Question 68056: The sum of $127 was didvided among 3 people so that the second received $5 less than twice as much as the first, and the third received $2 more than the second. How much did each person receive? \n" ); document.write( "
Algebra.Com's Answer #48362 by stanbon(75887)\"\" \"About 
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The sum of $127 was didvided among 3 people so that the second received $5 less than twice as much as the first, and the third received $2 more than the second. How much did each person receive?
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\n" ); document.write( "Let the amount the 1st received be x dollars.
\n" ); document.write( "Then 2nd person received 2x-5 dollars.
\n" ); document.write( "And 3rd person received 2x-5+2 = 2x-3 dollars.
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\n" ); document.write( "EQuATION:
\n" ); document.write( "Total dollars was 127
\n" ); document.write( "x+2x-5+2x-3 = 127
\n" ); document.write( "5x-8=127
\n" ); document.write( "5x=135
\n" ); document.write( "x=27 dollars for 1st person
\n" ); document.write( "2x-5=2*27-5=49 dollars for 2nd person
\n" ); document.write( "2x-3=2*27-3= 51 dollars
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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