document.write( "Question 801045: Hi! I have a problem that asks: \"Find the focus and directrix of the parabola from the given equation. \"\r
\n" ); document.write( "\n" ); document.write( "The first problem is: y^2=16x \r
\n" ); document.write( "\n" ); document.write( "I tried using this formula: \"(y-k)^2=4p (x-h) and only figured out the vertex, which in this case would be (0,0). I don't understand the rest. I tried finding the directrix and focus but I just don't understand how to at all. Please help. Thank you! :)
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Algebra.Com's Answer #483617 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Find the focus and directrix of the parabola from the given equation. \"
\n" ); document.write( "The first problem is: y^2=16x
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\n" ); document.write( "There are 4 different forms of equation for parabolas with vertices at the origin:
\n" ); document.write( "x^2=4py (parabola opens up)
\n" ); document.write( "x^2=-4py (parabola opens down)
\n" ); document.write( "y^2=4px (parabola opens right)
\n" ); document.write( "y^2=-4px (parabola opens left)
\n" ); document.write( "..
\n" ); document.write( "Equation of given parabola y^2=16x is the 3rd form listed
\n" ); document.write( "It is a parabola that opens right with vertex at (0,0)
\n" ); document.write( "Its axis of symmetry:y=0 or x-axis
\n" ); document.write( "4p=16
\n" ); document.write( "p=4
\n" ); document.write( "directrix:x=-4 (p-distance to the left of the vertex on the axis of symmetry
\n" ); document.write( "focus:(4,0)(p-distance to the right of the vertex on the axis of symmetry
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