document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=801700>Question 801700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangular plot of land is 50 yards shorter than 4 times the width. find the length if the perimeter is 900 yards  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483597 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483597\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length (L) = 4w - 50<BR>\n" );
document.write( "width = w<BR>\n" );
document.write( "perimeter = 900\r<BR>\n" );
document.write( "\n" );
document.write( "2L + 2w = p<BR>\n" );
document.write( "2(4w - 50) + 2w = 900<BR>\n" );
document.write( "8w - 100 + 2w = 900<BR>\n" );
document.write( "10w - 100 + 100 = 900 + 100<BR>\n" );
document.write( "10w = 1000<BR>\n" );
document.write( "10w/10 = 1000/10<BR>\n" );
document.write( "w = 100\r<BR>\n" );
document.write( "\n" );
document.write( "width = 100 yards<BR>\n" );
document.write( "lenth = 4(100) - 50<BR>\n" );
document.write( "      = 400 - 50<BR>\n" );
document.write( "      = 350 yards\r<BR>\n" );
document.write( "\n" );
document.write( "check:<BR>\n" );
document.write( "2(100) + 2(350) = 900<BR>\n" );
document.write( "200 + 700 = 900<BR>\n" );
document.write( "900 = 900 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );