document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=67971>Question 67971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive odd integers such that 9 times the first is the same as the sum of 3 times the second and 4 times the third. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48358 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find three consecutive odd integers<BR>\n" );
document.write( "x, (x+2), (x+4)<BR>\n" );
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document.write( " such that 9 times the first is the same as the sum of 3 times the second and 4 times the third.<BR>\n" );
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document.write( "9x = 3(x+2)+4(x+4)<BR>\n" );
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document.write( "9x = 3x + 6 + 4x + 16<BR>\n" );
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document.write( "9x = 7x + 22<BR>\n" );
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document.write( "9x - 7x = 22<BR>\n" );
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document.write( "2x = 22<BR>\n" );
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document.write( "x = 11<BR>\n" );
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document.write( "Check: 9(11) = 3(13) + 4(15) <BR>\n" );
document.write( "99 = 39 + 60 </SPAN>\n" );
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