document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=801424>Question 801424</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has three different acid solutions. The first acid solution contains 25%  acid, the second contains 45%  and the third contains 85% . He wants to use all three solutions to obtain a mixture of 50  liters containing 65%  acid, using 3  times as much of the 85%  solution as the 45%  solution. How many liters of each solution should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483546 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the amount of the 45% acid solution<BR>\n" );
document.write( "Then the amount of the 85% acid solution = 3x<BR>\n" );
document.write( "Since the total volume of the mixture is 50 l, the amount of the 25% solution is 50 - 3x - x = 50 - 4x<BR>\n" );
document.write( "The equation for the total amount of acid in the mixture is<BR>\n" );
document.write( "0.65*50 = 0.45x + 0.85*3x + 0.25(50 - 4x)<BR>\n" );
document.write( "Simplify and solve for x:<BR>\n" );
document.write( "0.45x + 2.55x + 12.5 - x = 32.5<BR>\n" );
document.write( "2x = 20<BR>\n" );
document.write( "x = 10<BR>\n" );
document.write( "So there 10 l of 45% solution, 30 l of 85% solution and 10 l of 25% solution </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );