document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=801383>Question 801383</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem. \r<BR>\n" );
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document.write( "If the perimeter of a rectangular closet is 40 feet and the width is one foot less than half the length, what are the dimensions of the length and width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483538 by </B><A HREF=/tutors/aboutme.mpl?userid=thejackal><B>thejackal(72)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thejackal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=thejackal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If P = 2L + 2W where L and W are Length and Width Respectively<BR>\n" );
document.write( "then <BR>\n" );
document.write( "40 = 2L + 2W;<BR>\n" );
document.write( "since W = (L/2)-1\r<BR>\n" );
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document.write( "then 40 = 2L + 2((L/2)-1)<BR>\n" );
document.write( "simplified to 40 = 3L - 2\r<BR>\n" );
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document.write( "42/3 = L\r<BR>\n" );
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document.write( "solve for L you will find that L = 14 <BR>\n" );
document.write( "plug that into the equation for W such <BR>\n" );
document.write( "that\r<BR>\n" );
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document.write( "W = (14/2)-1 = 6\r<BR>\n" );
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document.write( " </SPAN>\n" );
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