document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=801302>Question 801302</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a rectangle is 10a-6 metres and the width is 2a metres, what do I do to find out the length of this rectangle?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483521 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p = 10a - 6<BR>\n" );
document.write( "width = 2a<BR>\n" );
document.write( "length = L\r<BR>\n" );
document.write( "\n" );
document.write( "p = 2L + 2w<BR>\n" );
document.write( "2(2a) + 2L = 10a - 6<BR>\n" );
document.write( "4a + 2L = 10a - 6<BR>\n" );
document.write( "4a - 4a + 2L = 10a - 4a - 6<BR>\n" );
document.write( "2L = 6a - 6<BR>\n" );
document.write( "2L/2 = (6a  6)/2<BR>\n" );
document.write( "L = 3a - 3\r<BR>\n" );
document.write( "\n" );
document.write( "check:<BR>\n" );
document.write( "2(2a) + 2(3a - 3) = 120a - 6<BR>\n" );
document.write( "4a + 6a - 6 = 10a - 6<BR>\n" );
document.write( "10a - 6 = 10a - 6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );