document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=801333>Question 801333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 10 inches less than its length. If the perimeter is 112 inches, find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483519 by </B><A HREF=/tutors/aboutme.mpl?userid=waynest><B>waynest(281)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=waynest><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width (w) = L - 10<BR>\n" );
document.write( "length (L) = L<BR>\n" );
document.write( "p = 112\r<BR>\n" );
document.write( "\n" );
document.write( "p = 2L + 2w<BR>\n" );
document.write( "2L + 2(L - 10) = 112<BR>\n" );
document.write( "2L + 2L - 20 = 112<BR>\n" );
document.write( "4L - 20 + 20 = 112 + 20<BR>\n" );
document.write( "4L = 132<BR>\n" );
document.write( "4L/4 = 132/4<BR>\n" );
document.write( "L = 33\r<BR>\n" );
document.write( "\n" );
document.write( "check:<BR>\n" );
document.write( "2(33) + 2(33 - 10) = 112<BR>\n" );
document.write( "66 + 2(23) = 112<BR>\n" );
document.write( "66 + 46 = 112<BR>\n" );
document.write( "112 = 112 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );