document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=801158>Question 801158</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An alloy of metals is 25% copper.  Another alloy is 50% copper.  How much of each should be used to make 1000 grams of an alloy that is 45% copper? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483442 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An alloy of metals is 25% copper. Another alloy is 50% copper. How much of each should be used to make 1000 grams of an alloy that is 45% copper?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "copper + copper = copper<BR>\n" );
document.write( "0.25x + 0.50(1000-x) = 0.45*1000<BR>\n" );
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document.write( "25x + 50*1000 - 50x = 45*1000<BR>\n" );
document.write( "-25x = -5*1000<BR>\n" );
document.write( "x = (1/5)(1000)<BR>\n" );
document.write( "x = 200 grams (amt. of 25% alloy needed)<BR>\n" );
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document.write( "1000-x = 800 grams (amt. of 50% alloy needed)<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=============== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );