document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=800984>Question 800984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangular region has a perimeter of 150 meters. The first side is one-half of the second side. The third side is 20 meters shorter than the second side. What are the lengths of the three sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483393 by </B><A HREF=/tutors/aboutme.mpl?userid=Finavon><B>Finavon(81)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Finavon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let sides be a, b and c<BR>\n" );
document.write( "a+b+c=150 (1)<BR>\n" );
document.write( "2a=b so a=b/2<BR>\n" );
document.write( "c=b-20\r<BR>\n" );
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document.write( "substitute for a and c in (1)<BR>\n" );
document.write( "b/2 + b + b-20 = 150<BR>\n" );
document.write( "5b/2=170<BR>\n" );
document.write( "b=340/5 = 68<BR>\n" );
document.write( "a=68/2 = 34<BR>\n" );
document.write( "c=68-20= 48\r<BR>\n" );
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document.write( "Sides are 34, 68 and 48 m\r<BR>\n" );
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document.write( "Check perimeter = 34+68+48 = 150 </SPAN>\n" );
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