document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=800980>Question 800980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> After the morning rush at the neighborhood coffee shop, the tip jar contained $3.75 in coins. There was one less quarter than nickels. There are twice as many dimes as nickels. How many coins of each type were there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483390 by </B><A HREF=/tutors/aboutme.mpl?userid=Finavon><B>Finavon(81)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Finavon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483390\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let q, n and d be number of each coin, worth 25c, 5c and 10c<BR>\n" );
document.write( "25q+5n+10d=375<BR>\n" );
document.write( "q=n-1<BR>\n" );
document.write( "2n=d\r<BR>\n" );
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document.write( "substitute for d and q<BR>\n" );
document.write( "25n-25+5n+20n = 375<BR>\n" );
document.write( "50n=400 so n=8<BR>\n" );
document.write( "then d=16 and q=7<BR>\n" );
document.write( "8 nickels, 16 dimes and 7 quarters\r<BR>\n" );
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document.write( "Check: 25*7 + 5*8 + 10*16 = 175+40+160 = 375<BR>\n" );
document.write( " </SPAN>\n" );
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