document.write( "Question 800877: Ina Crespo rowed 20 miles down the Hashabee River in 2 hours, but the return trip took her 5 hours. Find the rate Ina rows in still water and the rate of the current. Let x represent the rate Ina can row in still water and let y represent the rate of the current water. \n" ); document.write( "
Algebra.Com's Answer #483331 by mananth(16946)\"\" \"About 
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boat speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current 5 hours
\n" ); document.write( "with current 2 hours
\n" ); document.write( "
\n" ); document.write( "Distance against 20 miles distance with 20 miles
\n" ); document.write( "t=d/r against current -
\n" ); document.write( "20.00 / ( x - y )= 5.00
\n" ); document.write( "5.00 ( x - y ) = 2.00
\n" ); document.write( "5.00 x - 5.00 y = 20.00 ....................1
\n" ); document.write( "
\n" ); document.write( "20.00 / ( x + y )= 2.00
\n" ); document.write( "2.00 ( x + y ) = 20.00
\n" ); document.write( "2.00 x + 2.00 y = 20.00 ...............2
\n" ); document.write( "Multiply (1) by 2.00
\n" ); document.write( "Multiply (2) by 5.00
\n" ); document.write( "we get
\n" ); document.write( "10.00 x + -10.00 y = 40.00
\n" ); document.write( "10.00 x + 10.00 y = 100.00
\n" ); document.write( "20.00 x = 140.00
\n" ); document.write( "/ 20.00
\n" ); document.write( "x = 7.00 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "5.00 x -5.00 y = 20.00
\n" ); document.write( "35.00 -5.00 -35.00 = 20.00
\n" ); document.write( "-5.00 y = 20.00
\n" ); document.write( "-5.00 y = -15.00 mph
\n" ); document.write( " y = 3.00
\n" ); document.write( "boat speed 7.00 mph
\n" ); document.write( "current speed 3.00 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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